# তিতাস গ্যাস কোম্পানী Assistant manager (General) এর নিয়োগ পরীক্ষার প্রশ্ন সমাধান ২০২১ - Titas Gas Exam Question Solution 2021 (TGTDCL)

## তিতাস গ্যাস কোম্পানী Assistant manager (General) এর নিয়োগ পরীক্ষার প্রশ্ন সমাধান ২০২১ - Titas Gas Exam Question Solution 2021 (TGTDCL)

Math Part ( Exam Taker IBA)
Solved by Shuvo Sarker Slokh
============================
46■
D/3 = 3H/5
=> D5 = 9H
=> D : H = 9 : 5
47■■
X/10 - X/12 = 3
=> 6X - 5X = 60×3
=> X = 180
48■■
CR => 7 : 3 = 70 : 30
20% = 5 : 4 = 70 : 56
40% = 5 : 7 = 30 : 42
Final [ 100 : 98 ] ie 2% loss
49■■
S : W => 2 : 3 = 8 : 12
S : W => 1 : 3 = 5 : 15
S : W => 3 : 7 = 6 : 14
8============5
=====6======
1=============2
X % = 1/3 ie 33.33%
50■■  83-63/.5 = 20×10/5 = 40 (Ans)
51■■
CP per kg at 10% => 22×10/11 = 20
14============ 
=======20======
2==============3
Ans ... 24
52■■ AS = 340/5 = 68
60===========80
=======68=====
12============8
=> 3 : 2 .... Ans : 3 hour
53■■
3 year ago = 27×3 = 81
Now , Sum = 81+9 = 90
5 year ago = 20×2 = 40
Now , Sum = 40+10 = 50
So , Age of Husband = 90-50 = 40 (Ans).
54■■ 320% Profit ie
CP : P : SP = 100 : 320 : 420
CP : P : SP = 125 : 295 : 420 [ As CP 25% increase and SP remains same ]
Required % = 295/420 = 70.23% (Ans)
55■■Let the fixed amount be Tk. X and  the cost of each unit  be TK. Y  Then
540y + X =  1800...........................(i)
and  620y + X =  2040 ............................(ii)
On subtracting (i) from (ii) , we get  80y =  240    => y = 3
putting y = 3 in  (i) , we get;
540 x 3  + x =  1800
= > (1800 - 1620) =  180.
Fixed charges = TK. 180, Charge per unit  =  TK. 3
Now , Total charges for consuming  500 units =  Tk. (180 + 500 x 3) = Tk. 1680.
56■■ AS = 61/9
36=============81
=======61=======
20=============25
=> 4 : 5 (TR)
Distance cover on foot => 4×4 = 16 km (Ans)
57■■
X : Y = 2.5 : 1 = 5 : 2 = 10 : 4
Y : Z = 4 : 1
So , X : Y : Z = 10 : 4 : 1
Z = 1800/15 = 120 (Ans)
58■■
Let , Total 100 individuals
A = 20
B = 60
None = 20
A/Q ,(60-20) ie 40 unit = 720
100 unit = 1800 (Ans)
59■■Here , Age of Captain 26 years and Wicketkeeper 29 years.
Let , Average was X years
A/Q ,
11X - 55 = 9 (X-1)
=> 11X - 9X = - 9 + 55
=> 2X = 46
=> X = 23 [Ans]
60■■
=> X^2 - 6X + 8 = 0
=> (X-4)(X-2) = 0 ....... [4×2 = 8 , 4+2 = 6 ]
=> X = 4 & 2
Ans ... (A)2 < X < 4

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